土壤物理指數運算的問題 - 土木
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By Carolina Franco
at 2009-04-01T17:44
at 2009-04-01T17:44
Table of Contents
題目:
1.今給定一土壤在不同飽和度下的乾密度值,但土壤的含水量始終維持定值
試求含水量w(題目已給乾密度值Rd1,Rd2,及對應之飽和度S1,S2)
2.推倒e=(Rsat-Rw)/(Rd-Rsat+Rw)
想法:
1.因題目未給定土粒子比重,先假設Gs=2.65,則由
Rd=Rs/(1+e)=Rm/(1+w).................(1)
Se=w*Gs..............................(2)
因題目指定含水量為常數,故Se=定值,即S1*e1=S2*e2,可以推得e1和e2之關係
再由Rd*(1+e)=Rs=Gs*Rw=定值,可以推得e1,e2
最後再由(2)式求得含水量w。
2.右式= Gs-1/(1+e)*Rw =Gs-1=...=e
---------------
Gs*Rw/(1+e)-(Gs-1)*Rw/(1+e)
第二題我想了好久總是不知道要乘上什麼才會等於左邊的孔隙比
麻煩板上的大家給一點靈感
還有第一題不知道我這樣算法是否合理
以上麻煩如果有想法的版友可以給予指正^^"
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Tags:
土木
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By Christine
at 2009-04-03T03:17
at 2009-04-03T03:17
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By Catherine
at 2009-04-06T18:06
at 2009-04-06T18:06
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By Xanthe
at 2009-04-09T15:34
at 2009-04-09T15:34
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By Frederic
at 2009-04-14T15:00
at 2009-04-14T15:00
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By Connor
at 2009-04-14T22:45
at 2009-04-14T22:45
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