鉸接時,節點自由度,該如何宣告 - 土木
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By Kyle
at 2011-07-16T10:40
at 2011-07-16T10:40
Table of Contents
: 如果X是橋軸方向 Y是側向 Z是垂直向
:
: Rx=1 (如果你的箱梁是放2個支承)
: Ry=0 hinge 彎矩不連續
: Rz=1 (1=變位一致 0=變位不連續)
:
:
: --
:
: Rx=1 (如果你的箱梁是放2個支承)
: Ry=0 hinge 彎矩不連續
: Rz=1 (1=變位一致 0=變位不連續)
:
:
: --
Tags:
土木
All Comments
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By Vanessa
at 2011-07-17T17:47
at 2011-07-17T17:47
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By Candice
at 2011-07-19T07:24
at 2011-07-19T07:24
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By Callum
at 2011-07-23T21:10
at 2011-07-23T21:10
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By Genevieve
at 2011-07-24T09:50
at 2011-07-24T09:50
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請問普考土木台中考區在哪裡呢?
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at 2011-07-15T21:13
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