關於測量學中的辛普森法 - 土木
By Andrew
at 2015-08-02T11:52
at 2015-08-02T11:52
Table of Contents
(代po)
這是在《測量學題解》(林宏麟,2014) 第十二章的問題:
在計算不規則圖形時,令 d 為間距,h_1, h_2, ..., h_n 為平行分割線之長度,則用辛普森法計算面積 A 時
若 n 為奇數:
A = d/3 [h_1 + 4 (h_2 + h_4 + ...) + 2 (h_3 + h_5 + ...) + h_n]
若 n 為偶數:
A = d/3 [h_1 + 4 (h_2 + h_4 + ...) + 2 (h_3 + h_5 + ...) + h_{n-1}] + d/2 (h_{n-1} + h_n)
問題:為什麼當 n 為偶數時,在前 n-1 塊用奇數情形的"辛普森",而後面兩塊卻是在算"梯形"?
有些書不特別分開強調奇偶數的狀況,這樣在考試時應該用哪一種算法?
謝謝
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