電機(甲) 專B 答案討論 - 國營工作討論
By Callum
at 2014-12-29T18:21
at 2014-12-29T18:21
Table of Contents
想跟大家討論一下 專B的答案 只提供 我自己會的題目
第一題
(1)相位常數B=377*√0.97m*0.0115u=1.259146*10^-3 忘了成377...WTF
(2)突波阻抗Zc=√L/C=290.43歐姆
(3)傳播速度v=1/√L*C=299409.25km/s
(4)波長 爛打=4990.15km
電力系統
後面不會
第四題
[1]
(1)甲機功率因素=0.6
(2)乙機之負載電流=608.276角度9.462度
[2]
(1)甲機之負載電流=832.399角度32.384度...沒有很確定
(2)乙機功率因素=0.994
更正 乙機PF=0.8
第五題
(1)此電動機之效率=90.703%
(2)輸入電壓提高至多少Vt=260...不大知道怎樣算應該 不正確
(3)不會
第六題
(1)此自偶變壓器損失=3k......算出來 忘了除0.95 我寫 2.85k 崩潰..
(2)此自偶變壓器容量=660kVA
(3)此自偶變壓器效率=99.548% ......損失算錯 這題應該也掰了 WTFFFFFF
--
第一題
(1)相位常數B=377*√0.97m*0.0115u=1.259146*10^-3 忘了成377...WTF
(2)突波阻抗Zc=√L/C=290.43歐姆
(3)傳播速度v=1/√L*C=299409.25km/s
(4)波長 爛打=4990.15km
電力系統
後面不會
第四題
[1]
(1)甲機功率因素=0.6
(2)乙機之負載電流=608.276角度9.462度
[2]
(1)甲機之負載電流=832.399角度32.384度...沒有很確定
(2)乙機功率因素=0.994
更正 乙機PF=0.8
第五題
(1)此電動機之效率=90.703%
(2)輸入電壓提高至多少Vt=260...不大知道怎樣算應該 不正確
(3)不會
第六題
(1)此自偶變壓器損失=3k......算出來 忘了除0.95 我寫 2.85k 崩潰..
(2)此自偶變壓器容量=660kVA
(3)此自偶變壓器效率=99.548% ......損失算錯 這題應該也掰了 WTFFFFFF
--
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