102年高考三級工程力學第五題 - 土木
By Michael
at 2013-12-11T15:00
at 2013-12-11T15:00
Table of Contents
題目:
http://farm6.staticflickr.com/5478/11319942594_ff39502bcb_c.jpg
小弟的算法:
-
h=(3-2*1/π)=2.36m
-
F=γw * A * h = 9.81*(2*π*1)*(1/4)*1*2.36=36.37 KN
- -
h = y =2.36m
yp = {{[1*(2*π*1*(1/4))^3]/12}/(2*π*1*(1/4))*1*2.36}+2.36=2.371m
Ans:合力F=36.37KN
合力位置:液面下2.371m匣門中央處
以上小弟所繪的圖形位置與計算過程,【觀念】是否有問題呢?
麻煩版上前輩們不吝嗇告知,謝謝!
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Tags:
土木
All Comments
By Daniel
at 2013-12-14T22:18
at 2013-12-14T22:18
By Oscar
at 2013-12-19T10:57
at 2013-12-19T10:57
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