一元三次方程式的解法 - 土木
By Cara
at 2011-08-25T19:36
at 2011-08-25T19:36
Table of Contents
※ [本文轉錄自 Math 看板 #1ELZC702 ]
作者: AlexChen (試煉石) 看板: Math
標題: [其他] 一元三次方程式的解法
時間: Thu Aug 25 19:33:23 2011
版上前輩們您好!
後學想要請教有關於【一元三次方程式】的解法,
除了用【試誤法】代數據去測試之外,還有其它解法嗎?
舉例來講:
8X^(3) - 9LX^(2) + L^(2)
這個可以拆解成:
8X^(3) - 9LX^(2) + L^(2) = [ 8X^(2) - LX - L^(2) ] * (X-L)
這樣可以變成一元二次方程式,X = 0.422L
但是後學有個疑問:
(1) (X-L)怎麼出來的?該如何去判斷呢?
(2) 若遇到不能拆解的方程式,請問還有甚麼解法呢?
舉例:X^(3) + X^(2) + X + 1 = 0
遇到如上式不能拆解的方程式,又有甚麼解法可以解呢?
麻煩不吝嗇告知,後學在此感激不盡,謝謝!
--
歲寒松柏古栽培,雨雪風霜總不摧,
異日必當成大用,功名作個棟樑材。
--
作者: AlexChen (試煉石) 看板: Math
標題: [其他] 一元三次方程式的解法
時間: Thu Aug 25 19:33:23 2011
版上前輩們您好!
後學想要請教有關於【一元三次方程式】的解法,
除了用【試誤法】代數據去測試之外,還有其它解法嗎?
舉例來講:
8X^(3) - 9LX^(2) + L^(2)
這個可以拆解成:
8X^(3) - 9LX^(2) + L^(2) = [ 8X^(2) - LX - L^(2) ] * (X-L)
這樣可以變成一元二次方程式,X = 0.422L
但是後學有個疑問:
(1) (X-L)怎麼出來的?該如何去判斷呢?
(2) 若遇到不能拆解的方程式,請問還有甚麼解法呢?
舉例:X^(3) + X^(2) + X + 1 = 0
遇到如上式不能拆解的方程式,又有甚麼解法可以解呢?
麻煩不吝嗇告知,後學在此感激不盡,謝謝!
--
歲寒松柏古栽培,雨雪風霜總不摧,
異日必當成大用,功名作個棟樑材。
--
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土木
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