一題力學問題 - 土木
By Necoo
at 2013-06-22T21:42
at 2013-06-22T21:42
Table of Contents
※ 引述《sweetycool (tina)》之銘言:
: http://ppt.cc/gff1 (題目)
: http://ppt.cc/1D~a (解答)
: 有點疑問會造成c點的變位看自由體圖的外力
: 應該只有 M0 跟 F
: 不知道為什麼會多一個FL的力矩
: 謝謝
ab桿件承受一個彎矩力,ab桿件最大撓度δmax=M0*L^2/16EI
彈簧變為δ=P/K=-[Px/(2EI/L^3)]=M0*L^2/16EI
Px = -M0/(L*8) (←)
Rbx = -M0/(L*8) (→)
Mb = -M0/8 (順時針轉)
設ΣMa=0
M0 + (-M0/8) - Rby*L = 0
Rby = (7/8)M0/L (↑)
Ray = (7/8)M0/L (↓)
ANS:
Ray = (7/8)M0/L (↓)
Rby = (7/8)M0/L (↑)
Rbx = -M0/(8L) (→)
--
: http://ppt.cc/gff1 (題目)
: http://ppt.cc/1D~a (解答)
: 有點疑問會造成c點的變位看自由體圖的外力
: 應該只有 M0 跟 F
: 不知道為什麼會多一個FL的力矩
: 謝謝
ab桿件承受一個彎矩力,ab桿件最大撓度δmax=M0*L^2/16EI
彈簧變為δ=P/K=-[Px/(2EI/L^3)]=M0*L^2/16EI
Px = -M0/(L*8) (←)
Rbx = -M0/(L*8) (→)
Mb = -M0/8 (順時針轉)
設ΣMa=0
M0 + (-M0/8) - Rby*L = 0
Rby = (7/8)M0/L (↑)
Ray = (7/8)M0/L (↓)
ANS:
Ray = (7/8)M0/L (↓)
Rby = (7/8)M0/L (↑)
Rbx = -M0/(8L) (→)
--
Tags:
土木
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