103年台科大研究所的壓密沉陷與時間 - 土木
By Jessica
at 2015-01-28T02:10
at 2015-01-28T02:10
Table of Contents
不好意思 請各位前輩幫幫我表弟
他今年要考台科大的大地組
但寫到有一題考古題 數據有點怪 答案跟同學也不太一樣
所以想來請問一下前輩們 一二題
http://i.imgur.com/wUzRNUa.jpg
http://i.imgur.com/p4SYScx.jpg
他先算
出垂直有效覆土應力 =82.14 kN/m^3 < 預壓密應力 =150 kN/m^3
因為地表外力作用後 82.14+100= 182.14 kN/m^3 > 預壓密應力
所以Sc改寫成 12/1+0.82 x (Cr log(150/82.14)+Cc log(182.14/150))
Sc= 0.288m =28.8cm
Uavg = 90% Tv=0.848 Hdr=12/2 (上下排水) _Cv= 0.002cm^2/sec
0.848x6^2=0.002 x (10^-2)^2 x t
t= 152640000 sec = 1766.6 day
請問各位前輩 表弟這樣算式是錯還是對? 謝謝各位回答
--
他今年要考台科大的大地組
但寫到有一題考古題 數據有點怪 答案跟同學也不太一樣
所以想來請問一下前輩們 一二題
http://i.imgur.com/wUzRNUa.jpg
http://i.imgur.com/p4SYScx.jpg
他先算
出垂直有效覆土應力 =82.14 kN/m^3 < 預壓密應力 =150 kN/m^3
因為地表外力作用後 82.14+100= 182.14 kN/m^3 > 預壓密應力
所以Sc改寫成 12/1+0.82 x (Cr log(150/82.14)+Cc log(182.14/150))
Sc= 0.288m =28.8cm
Uavg = 90% Tv=0.848 Hdr=12/2 (上下排水) _Cv= 0.002cm^2/sec
0.848x6^2=0.002 x (10^-2)^2 x t
t= 152640000 sec = 1766.6 day
請問各位前輩 表弟這樣算式是錯還是對? 謝謝各位回答
--
Tags:
土木
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By Rachel
at 2015-01-29T02:03
at 2015-01-29T02:03
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at 2015-01-29T07:40
at 2015-01-29T07:40
By Puput
at 2015-02-02T01:04
at 2015-02-02T01:04
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at 2015-02-03T19:09
at 2015-02-03T19:09
By Jake
at 2015-02-05T05:57
at 2015-02-05T05:57
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