97-臺電招考-專業2-問答5 - 土木
By Christine
at 2011-01-27T22:58
at 2011-01-27T22:58
Table of Contents
請教版上的高手:
已知擋土牆高10M,地下水位在地下2M若擋土牆在無側向位移狀況下,牆背下方10公尺處
之應力為多少?
(0~2M γ=18.2kn/m3 2~10 γ(sat)=19.82kn/m3 c=0 K0=0.5)
想請教 1.本題所要求的是指總側向土壓力嗎?
2.做法
(1)0~2M (18.2*2)*2*0.5=36.4kn
(2)2~8M A.土側向力{[18.2*2+(19.62-9.81)*8]*0.5}*8*0.5=386.72kn
B.地下水位側向力(9.81*8)*8*0.5=313.92kn
(3)總側向力 (1)+(2)=36.4+(386.72+313.92)=737.04kn
總垂直立 737.04/0.5=1474.08kn
--
已知擋土牆高10M,地下水位在地下2M若擋土牆在無側向位移狀況下,牆背下方10公尺處
之應力為多少?
(0~2M γ=18.2kn/m3 2~10 γ(sat)=19.82kn/m3 c=0 K0=0.5)
想請教 1.本題所要求的是指總側向土壓力嗎?
2.做法
(1)0~2M (18.2*2)*2*0.5=36.4kn
(2)2~8M A.土側向力{[18.2*2+(19.62-9.81)*8]*0.5}*8*0.5=386.72kn
B.地下水位側向力(9.81*8)*8*0.5=313.92kn
(3)總側向力 (1)+(2)=36.4+(386.72+313.92)=737.04kn
總垂直立 737.04/0.5=1474.08kn
--
Tags:
土木
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