慣性矩與應力公式比較疑問 - 土木
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By Rae
at 2013-12-11T15:19
at 2013-12-11T15:19
Table of Contents
※ 引述《sweetycool (tina)》之銘言:
: http://ppt.cc/aI1x
: 慣性矩
: http://ppt.cc/LJYH
: 應力
: http://ppt.cc/LJYH
: 應變
: 前面 τ可以類比於 γ/2 與 -I
: 但想問一下為什麼慣性矩的公式前面沒有負號呢?
: 謝謝
平面應力應變常用公式:
σθ= (σx+σy)/2 +[(σx-σy)/2]*cos2θ-τxy*sin2θ
τθ= [(σx-σy)/2]*sin2θ+τxy*cos2θ
εθ= (εx+εy)/2 +[(εx-εy)/2]*cos2θ-γxy*sin2θ
γθ/2= [(εx-εy)/2]*sin2θ+(γxy/2)*cos2θ
慣性矩的應用公式如上所類推
--
: http://ppt.cc/aI1x
: 慣性矩
: http://ppt.cc/LJYH
: 應力
: http://ppt.cc/LJYH
: 應變
: 前面 τ可以類比於 γ/2 與 -I
: 但想問一下為什麼慣性矩的公式前面沒有負號呢?
: 謝謝
平面應力應變常用公式:
σθ= (σx+σy)/2 +[(σx-σy)/2]*cos2θ-τxy*sin2θ
τθ= [(σx-σy)/2]*sin2θ+τxy*cos2θ
εθ= (εx+εy)/2 +[(εx-εy)/2]*cos2θ-γxy*sin2θ
γθ/2= [(εx-εy)/2]*sin2θ+(γxy/2)*cos2θ
慣性矩的應用公式如上所類推
--
Tags:
土木
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By Michael
at 2013-12-14T06:45
at 2013-12-14T06:45
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at 2013-12-14T10:04
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at 2013-12-17T11:43
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